Base | Representation |
---|---|
bin | 1100010101000001001110… |
… | …0000000111011011101011 |
3 | 1202222212110020222210211022 |
4 | 3011100103200013123223 |
5 | 3234042114424103311 |
6 | 44455105413523055 |
7 | 2566222403446625 |
oct | 305202340073353 |
9 | 52885406883738 |
10 | 13555243972331 |
11 | 4356823924276 |
12 | 162b11b94348b |
13 | 77433c1166c9 |
14 | 34c1121c7c15 |
15 | 18790a2095db |
hex | c54138076eb |
13555243972331 has 2 divisors, whose sum is σ = 13555243972332. Its totient is φ = 13555243972330.
The previous prime is 13555243972327. The next prime is 13555243972343. The reversal of 13555243972331 is 13327934255531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13555243972331 - 22 = 13555243972327 is a prime.
It is a super-2 number, since 2×135552439723312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13555243972351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6777621986165 + 6777621986166.
It is an arithmetic number, because the mean of its divisors is an integer number (6777621986166).
Almost surely, 213555243972331 is an apocalyptic number.
13555243972331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13555243972331 is an equidigital number, since it uses as much as digits as its factorization.
13555243972331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10206000, while the sum is 53.
The spelling of 13555243972331 in words is "thirteen trillion, five hundred fifty-five billion, two hundred forty-three million, nine hundred seventy-two thousand, three hundred thirty-one".
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