Base | Representation |
---|---|
bin | 1100010101000001100011… |
… | …0001100001010110111111 |
3 | 1202222212200102102110122222 |
4 | 3011100120301201112333 |
5 | 3234042310044433210 |
6 | 44455122253355555 |
7 | 2566224526321625 |
oct | 305203061412677 |
9 | 52885612373588 |
10 | 13555332421055 |
11 | 4356869846097 |
12 | 162b145498bbb |
13 | 774354544529 |
14 | 34c11dc4d515 |
15 | 187912d7b655 |
hex | c5418c615bf |
13555332421055 has 16 divisors (see below), whose sum is σ = 16464075919200. Its totient is φ = 10712508187008.
The previous prime is 13555332421027. The next prime is 13555332421079. The reversal of 13555332421055 is 55012423355531.
It is a cyclic number.
It is not a de Polignac number, because 13555332421055 - 226 = 13555265312191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13555332420997 and 13555332421015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2361221 + ... + 5717169.
It is an arithmetic number, because the mean of its divisors is an integer number (1029004744950).
Almost surely, 213555332421055 is an apocalyptic number.
13555332421055 is a deficient number, since it is larger than the sum of its proper divisors (2908743498145).
13555332421055 is an equidigital number, since it uses as much as digits as its factorization.
13555332421055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3365770.
The product of its (nonzero) digits is 1350000, while the sum is 44.
Adding to 13555332421055 its reverse (55012423355531), we get a palindrome (68567755776586).
The spelling of 13555332421055 in words is "thirteen trillion, five hundred fifty-five billion, three hundred thirty-two million, four hundred twenty-one thousand, fifty-five".
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