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13555332421055 = 58397333355949
BaseRepresentation
bin1100010101000001100011…
…0001100001010110111111
31202222212200102102110122222
43011100120301201112333
53234042310044433210
644455122253355555
72566224526321625
oct305203061412677
952885612373588
1013555332421055
114356869846097
12162b145498bbb
13774354544529
1434c11dc4d515
15187912d7b655
hexc5418c615bf

13555332421055 has 16 divisors (see below), whose sum is σ = 16464075919200. Its totient is φ = 10712508187008.

The previous prime is 13555332421027. The next prime is 13555332421079. The reversal of 13555332421055 is 55012423355531.

It is a cyclic number.

It is not a de Polignac number, because 13555332421055 - 226 = 13555265312191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13555332420997 and 13555332421015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2361221 + ... + 5717169.

It is an arithmetic number, because the mean of its divisors is an integer number (1029004744950).

Almost surely, 213555332421055 is an apocalyptic number.

13555332421055 is a deficient number, since it is larger than the sum of its proper divisors (2908743498145).

13555332421055 is an equidigital number, since it uses as much as digits as its factorization.

13555332421055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3365770.

The product of its (nonzero) digits is 1350000, while the sum is 44.

Adding to 13555332421055 its reverse (55012423355531), we get a palindrome (68567755776586).

The spelling of 13555332421055 in words is "thirteen trillion, five hundred fifty-five billion, three hundred thirty-two million, four hundred twenty-one thousand, fifty-five".

Divisors: 1 5 83 415 9733 48665 807839 3355949 4039195 16779745 278543767 1392718835 32663451617 163317258085 2711066484211 13555332421055