Base | Representation |
---|---|
bin | 11001001111111100… |
… | …01000000010000111 |
3 | 1021222201001201000211 |
4 | 30213332020002013 |
5 | 210230201433033 |
6 | 10121033220251 |
7 | 656626561444 |
oct | 144776100207 |
9 | 37881051024 |
10 | 13555499143 |
11 | 58267a915a |
12 | 2763861687 |
13 | 13804b9214 |
14 | 92844a9cb |
15 | 5450ce2cd |
hex | 327f88087 |
13555499143 has 4 divisors (see below), whose sum is σ = 13576007368. Its totient is φ = 13534990920.
The previous prime is 13555499141. The next prime is 13555499147. The reversal of 13555499143 is 34199455531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13555499143 - 21 = 13555499141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13555499141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10253121 + ... + 10254442.
It is an arithmetic number, because the mean of its divisors is an integer number (3394001842).
Almost surely, 213555499143 is an apocalyptic number.
13555499143 is a deficient number, since it is larger than the sum of its proper divisors (20508225).
13555499143 is an equidigital number, since it uses as much as digits as its factorization.
13555499143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20508224.
The product of its digits is 1458000, while the sum is 49.
The spelling of 13555499143 in words is "thirteen billion, five hundred fifty-five million, four hundred ninety-nine thousand, one hundred forty-three".
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