Base | Representation |
---|---|
bin | 11001010000000100… |
… | …10101001001011001 |
3 | 1021222210010201002101 |
4 | 30220002111021121 |
5 | 210230442221213 |
6 | 10121113003401 |
7 | 656642132224 |
oct | 145002251131 |
9 | 37883121071 |
10 | 13556601433 |
11 | 5827391341 |
12 | 27640b3561 |
13 | 13807b3b6b |
14 | 9286565bb |
15 | 54524abdd |
hex | 328095259 |
13556601433 has 8 divisors (see below), whose sum is σ = 13598303040. Its totient is φ = 13514962320.
The previous prime is 13556601407. The next prime is 13556601451. The reversal of 13556601433 is 33410665531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13556601433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13556601392 and 13556601401.
It is not an unprimeable number, because it can be changed into a prime (13556601133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 438966 + ... + 468832.
It is an arithmetic number, because the mean of its divisors is an integer number (1699787880).
Almost surely, 213556601433 is an apocalyptic number.
It is an amenable number.
13556601433 is a deficient number, since it is larger than the sum of its proper divisors (41701607).
13556601433 is an equidigital number, since it uses as much as digits as its factorization.
13556601433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31247.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 13556601433 in words is "thirteen billion, five hundred fifty-six million, six hundred one thousand, four hundred thirty-three".
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