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135657543523503 = 361741298052041
BaseRepresentation
bin11110110110000100111011…
…101100010101110010101111
3122210022201211110021100011110
4132312010323230111302233
5120240103122120223003
61200304114250123103
740400635251202401
oct3666047354256257
9583281743240143
10135657543523503
113a25204a809181
121326b410a20493
135a905b3b32c31
14256dc0831ab71
1510a3b6d8aaa03
hex7b613bb15caf

135657543523503 has 8 divisors (see below), whose sum is σ = 183841916906416. Its totient is φ = 88955766244800.

The previous prime is 135657543523501. The next prime is 135657543523519. The reversal of 135657543523503 is 305325345756531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 135657543523503 - 21 = 135657543523501 is a prime.

It is a super-2 number, since 2×1356575435235032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135657543523501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 370649025838 + ... + 370649026203.

It is an arithmetic number, because the mean of its divisors is an integer number (22980239613302).

Almost surely, 2135657543523503 is an apocalyptic number.

135657543523503 is a deficient number, since it is larger than the sum of its proper divisors (48184373382913).

135657543523503 is an equidigital number, since it uses as much as digits as its factorization.

135657543523503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 741298052105.

The product of its (nonzero) digits is 85050000, while the sum is 57.

The spelling of 135657543523503 in words is "one hundred thirty-five trillion, six hundred fifty-seven billion, five hundred forty-three million, five hundred twenty-three thousand, five hundred three".

Divisors: 1 3 61 183 741298052041 2223894156123 45219181174501 135657543523503