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1357121746681 = 1425195229931
BaseRepresentation
bin10011101111111010110…
…000100111011011111001
311210201222010222211200121
4103233322300213123321
5134213341131343211
62515241512533241
7200022512341111
oct23577260473371
94721863884617
101357121746681
114836089339a8
1219b0293b1221
139ac8c45904c
1449983a88041
152547db32271
hex13bfac276f9

1357121746681 has 4 divisors (see below), whose sum is σ = 1357216990864. Its totient is φ = 1357026502500.

The previous prime is 1357121746667. The next prime is 1357121746693. The reversal of 1357121746681 is 1866471217531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1357121746681 - 27 = 1357121746553 is a prime.

It is a super-2 number, since 2×13571217466812 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1357121756681) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47600715 + ... + 47629216.

It is an arithmetic number, because the mean of its divisors is an integer number (339304247716).

Almost surely, 21357121746681 is an apocalyptic number.

It is an amenable number.

1357121746681 is a deficient number, since it is larger than the sum of its proper divisors (95244183).

1357121746681 is an equidigital number, since it uses as much as digits as its factorization.

1357121746681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95244182.

The product of its digits is 1693440, while the sum is 52.

The spelling of 1357121746681 in words is "one trillion, three hundred fifty-seven billion, one hundred twenty-one million, seven hundred forty-six thousand, six hundred eighty-one".

Divisors: 1 14251 95229931 1357121746681