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1357121746693 is a prime number
BaseRepresentation
bin10011101111111010110…
…000100111011100000101
311210201222010222211201001
4103233322300213130011
5134213341131343233
62515241512533301
7200022512341126
oct23577260473405
94721863884631
101357121746693
11483608933a09
1219b0293b1231
139ac8c45905b
1449983a8804d
152547db3227d
hex13bfac27705

1357121746693 has 2 divisors, whose sum is σ = 1357121746694. Its totient is φ = 1357121746692.

The previous prime is 1357121746667. The next prime is 1357121746741. The reversal of 1357121746693 is 3966471217531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 818883826084 + 538237920609 = 904922^2 + 733647^2 .

It is an emirp because it is prime and its reverse (3966471217531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1357121746693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1357121746663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678560873346 + 678560873347.

It is an arithmetic number, because the mean of its divisors is an integer number (678560873347).

Almost surely, 21357121746693 is an apocalyptic number.

It is an amenable number.

1357121746693 is a deficient number, since it is larger than the sum of its proper divisors (1).

1357121746693 is an equidigital number, since it uses as much as digits as its factorization.

1357121746693 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5715360, while the sum is 55.

The spelling of 1357121746693 in words is "one trillion, three hundred fifty-seven billion, one hundred twenty-one million, seven hundred forty-six thousand, six hundred ninety-three".