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135730214117 = 154043881119
BaseRepresentation
bin111111001101000100…
…1101011010011100101
3110222100021100021122022
41332122021223103211
54210433413322432
6142204213312525
712543343532651
oct1763211532345
9428307307568
10135730214117
1152621192883
122237b935745
13ca510c1084
1467d852ba61
1537e5e59b12
hex1f9a26b4e5

135730214117 has 4 divisors (see below), whose sum is σ = 135731249280. Its totient is φ = 135729178956.

The previous prime is 135730214083. The next prime is 135730214141. The reversal of 135730214117 is 711412037531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 711412037531 = 1354724002887.

It is a cyclic number.

It is not a de Polignac number, because 135730214117 - 216 = 135730148581 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135730214167) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286517 + ... + 594602.

It is an arithmetic number, because the mean of its divisors is an integer number (33932812320).

Almost surely, 2135730214117 is an apocalyptic number.

It is an amenable number.

135730214117 is a deficient number, since it is larger than the sum of its proper divisors (1035163).

135730214117 is an equidigital number, since it uses as much as digits as its factorization.

135730214117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1035162.

The product of its (nonzero) digits is 17640, while the sum is 35.

The spelling of 135730214117 in words is "one hundred thirty-five billion, seven hundred thirty million, two hundred fourteen thousand, one hundred seventeen".

Divisors: 1 154043 881119 135730214117