Base | Representation |
---|---|
bin | 1100010110001010111110… |
… | …0110011110100000000001 |
3 | 1210001202120001220011012001 |
4 | 3011202233212132200001 |
5 | 3234403141421121221 |
6 | 44512142154304001 |
7 | 2600523133355041 |
oct | 305425746364001 |
9 | 53052501804161 |
10 | 13575042754561 |
11 | 4364163809412 |
12 | 1632b26428001 |
13 | 776175bcb972 |
14 | 34d06d891721 |
15 | 1881b847a391 |
hex | c58af99e801 |
13575042754561 has 8 divisors (see below), whose sum is σ = 13798370419200. Its totient is φ = 13351740444240.
The previous prime is 13575042754549. The next prime is 13575042754657. The reversal of 13575042754561 is 16545724057531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13575042754561 - 219 = 13575042230273 is a prime.
It is a super-3 number, since 3×135750427545613 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13575042751561) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5257441 + ... + 7402078.
It is an arithmetic number, because the mean of its divisors is an integer number (1724796302400).
Almost surely, 213575042754561 is an apocalyptic number.
It is an amenable number.
13575042754561 is a deficient number, since it is larger than the sum of its proper divisors (223327664639).
13575042754561 is a wasteful number, since it uses less digits than its factorization.
13575042754561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12677159.
The product of its (nonzero) digits is 17640000, while the sum is 55.
The spelling of 13575042754561 in words is "thirteen trillion, five hundred seventy-five billion, forty-two million, seven hundred fifty-four thousand, five hundred sixty-one".
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