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13575042230273 is a prime number
BaseRepresentation
bin1100010110001010111110…
…0100011110100000000001
31210001202120000220111222222
43011202233210132200001
53234403141302332043
644512142135140425
72600523126042356
oct305425744364001
953052500814888
1013575042230273
114364163490517
121632b26214715
13776175a77134
1434d06d79662d
151881b83c4d68
hexc58af91e801

13575042230273 has 2 divisors, whose sum is σ = 13575042230274. Its totient is φ = 13575042230272.

The previous prime is 13575042230027. The next prime is 13575042230339. The reversal of 13575042230273 is 37203224057531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11556960599809 + 2018081630464 = 3399553^2 + 1420592^2 .

It is a cyclic number.

It is not a de Polignac number, because 13575042230273 - 228 = 13574773794817 is a prime.

It is a super-3 number, since 3×135750422302733 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13575042232273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6787521115136 + 6787521115137.

It is an arithmetic number, because the mean of its divisors is an integer number (6787521115137).

Almost surely, 213575042230273 is an apocalyptic number.

It is an amenable number.

13575042230273 is a deficient number, since it is larger than the sum of its proper divisors (1).

13575042230273 is an equidigital number, since it uses as much as digits as its factorization.

13575042230273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 44.

The spelling of 13575042230273 in words is "thirteen trillion, five hundred seventy-five billion, forty-two million, two hundred thirty thousand, two hundred seventy-three".