13600324823053 has 4 divisors (see below), whose sum is σ = 13967901169660. Its totient is φ = 13232748476448.

The previous prime is 13600324823017. The next prime is 13600324823077. The reversal of 13600324823053 is 35032842300631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13085278900164 + 515045922889 = 3617358^2 + 717667^2 .

It is a cyclic number.

It is not a de Polignac number, because 13600324823053 - 2²⁵ = 13600291268621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13600324822997 and 13600324823015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13600324823083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183788173248 + ... + 183788173321.

It is an arithmetic number, because the mean of its divisors is an integer number (3491975292415).

Almost surely, 2^{13600324823053} is an apocalyptic number.

It is an amenable number.

13600324823053 is a deficient number, since it is larger than the sum of its proper divisors (367576346607).

13600324823053 is an equidigital number, since it uses as much as digits as its factorization.

13600324823053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367576346606.

The product of its (nonzero) digits is 311040, while the sum is 40.

The spelling of 13600324823053 in words is "thirteen trillion, six hundred billion, three hundred twenty-four million, eight hundred twenty-three thousand, fifty-three".