Base | Representation |
---|---|
bin | 111111010101001110… |
… | …0010100101001111111 |
3 | 111000001022122112212212 |
4 | 1332222130110221333 |
5 | 4212013401200120 |
6 | 142251255451035 |
7 | 12553202665145 |
oct | 1765234245177 |
9 | 430038575785 |
10 | 136003537535 |
11 | 527514a67a8 |
12 | 22437386a7b |
13 | ca9590b7c8 |
14 | 6822959595 |
15 | 380ee496c5 |
hex | 1faa714a7f |
136003537535 has 4 divisors (see below), whose sum is σ = 163204245048. Its totient is φ = 108802830024.
The previous prime is 136003537531. The next prime is 136003537589. The reversal of 136003537535 is 535735300631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136003537535 - 22 = 136003537531 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 136003537492 and 136003537501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136003537531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13600353749 + ... + 13600353758.
It is an arithmetic number, because the mean of its divisors is an integer number (40801061262).
Almost surely, 2136003537535 is an apocalyptic number.
136003537535 is a deficient number, since it is larger than the sum of its proper divisors (27200707513).
136003537535 is an equidigital number, since it uses as much as digits as its factorization.
136003537535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27200707512.
The product of its (nonzero) digits is 425250, while the sum is 41.
The spelling of 136003537535 in words is "one hundred thirty-six billion, three million, five hundred thirty-seven thousand, five hundred thirty-five".
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