Base | Representation |
---|---|
bin | 1100010111101100001100… |
… | …1000011101100000000001 |
3 | 1210011020220211220111002112 |
4 | 3011323003020131200001 |
5 | 3240320113344443431 |
6 | 44532135542025105 |
7 | 2602435635314450 |
oct | 305730310354001 |
9 | 53136824814075 |
10 | 13601140234241 |
11 | 437423609913a |
12 | 1637baa418195 |
13 | 778774912931 |
14 | 3504278bcb97 |
15 | 188be4686c2b |
hex | c5ec321d801 |
13601140234241 has 16 divisors (see below), whose sum is σ = 15794645260800. Its totient is φ = 11471263771968.
The previous prime is 13601140234193. The next prime is 13601140234259. The reversal of 13601140234241 is 14243204110631.
It is not a de Polignac number, because 13601140234241 - 214 = 13601140217857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13601140234198 and 13601140234207.
It is not an unprimeable number, because it can be changed into a prime (13601140234541) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41809286 + ... + 42133343.
It is an arithmetic number, because the mean of its divisors is an integer number (987165328800).
Almost surely, 213601140234241 is an apocalyptic number.
It is an amenable number.
13601140234241 is a deficient number, since it is larger than the sum of its proper divisors (2193505026559).
13601140234241 is an equidigital number, since it uses as much as digits as its factorization.
13601140234241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83943008.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 13601140234241 its reverse (14243204110631), we get a palindrome (27844344344872).
The spelling of 13601140234241 in words is "thirteen trillion, six hundred one billion, one hundred forty million, two hundred thirty-four thousand, two hundred forty-one".
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