Base | Representation |
---|---|
bin | 11110111011010001011001… |
… | …101111101111101101000011 |
3 | 122211120212021110100020102010 |
4 | 132323101121233233231003 |
5 | 120311430224141034430 |
6 | 1201140113521424003 |
7 | 40435503564300540 |
oct | 3673213157575503 |
9 | 584525243306363 |
10 | 136014530018115 |
11 | 3a37a490338311 |
12 | 1330863aa9b003 |
13 | 5ab8165c89228 |
14 | 25831d19d1bc7 |
15 | 10ad0b3e5bcb0 |
hex | 7bb459befb43 |
136014530018115 has 64 divisors (see below), whose sum is σ = 251044335452160. Its totient is φ = 61595093239680.
The previous prime is 136014530018113. The next prime is 136014530018243. The reversal of 136014530018115 is 511810035410631.
It is not a de Polignac number, because 136014530018115 - 21 = 136014530018113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (136014530018113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 409675630 + ... + 410007500.
It is an arithmetic number, because the mean of its divisors is an integer number (3922567741440).
Almost surely, 2136014530018115 is an apocalyptic number.
136014530018115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
136014530018115 is a deficient number, since it is larger than the sum of its proper divisors (115029805434045).
136014530018115 is a wasteful number, since it uses less digits than its factorization.
136014530018115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 368472.
The product of its (nonzero) digits is 43200, while the sum is 39.
Adding to 136014530018115 its reverse (511810035410631), we get a palindrome (647824565428746).
The spelling of 136014530018115 in words is "one hundred thirty-six trillion, fourteen billion, five hundred thirty million, eighteen thousand, one hundred fifteen".
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