Base | Representation |
---|---|
bin | 11110111011010011100000… |
… | …000100011010101111010011 |
3 | 122211121002002111211020221002 |
4 | 132323103200010122233103 |
5 | 120311444333044143321 |
6 | 1201141125303252215 |
7 | 40435613460266225 |
oct | 3673234004325723 |
9 | 584532074736832 |
10 | 136016783584211 |
11 | 3a380437423932 |
12 | 13308b6974a06b |
13 | 5ab8434b241aa |
14 | 2583367014415 |
15 | 10ad196c0a20b |
hex | 7bb4e011abd3 |
136016783584211 has 4 divisors (see below), whose sum is σ = 138910757703072. Its totient is φ = 133122809465352.
The previous prime is 136016783584111. The next prime is 136016783584229. The reversal of 136016783584211 is 112485387610631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136016783584211 - 230 = 136015709842387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136016783584111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1446987059360 + ... + 1446987059453.
It is an arithmetic number, because the mean of its divisors is an integer number (34727689425768).
Almost surely, 2136016783584211 is an apocalyptic number.
136016783584211 is a deficient number, since it is larger than the sum of its proper divisors (2893974118861).
136016783584211 is an equidigital number, since it uses as much as digits as its factorization.
136016783584211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2893974118860.
The product of its (nonzero) digits is 5806080, while the sum is 56.
The spelling of 136016783584211 in words is "one hundred thirty-six trillion, sixteen billion, seven hundred eighty-three million, five hundred eighty-four thousand, two hundred eleven".
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