Base | Representation |
---|---|
bin | 10011110010110011001… |
… | …101111110100010101011 |
3 | 11211000221211020010021002 |
4 | 103302303031332202223 |
5 | 134241210402414433 |
6 | 2520512543105215 |
7 | 200162301032306 |
oct | 23626315764253 |
9 | 4730854203232 |
10 | 1360216451243 |
11 | 4849567a9281 |
12 | 19b7518a220b |
13 | 9b36364b990 |
14 | 49b98aa3b3d |
15 | 255b06819e8 |
hex | 13cb337e8ab |
1360216451243 has 4 divisors (see below), whose sum is σ = 1464848485968. Its totient is φ = 1255584416520.
The previous prime is 1360216451233. The next prime is 1360216451311. The reversal of 1360216451243 is 3421546120631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1360216451243 - 238 = 1085338544299 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1360216451197 and 1360216451206.
It is not an unprimeable number, because it can be changed into a prime (1360216451233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52316017343 + ... + 52316017368.
It is an arithmetic number, because the mean of its divisors is an integer number (366212121492).
Almost surely, 21360216451243 is an apocalyptic number.
1360216451243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1360216451243 is a deficient number, since it is larger than the sum of its proper divisors (104632034725).
1360216451243 is a wasteful number, since it uses less digits than its factorization.
1360216451243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104632034724.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 1360216451243 in words is "one trillion, three hundred sixty billion, two hundred sixteen million, four hundred fifty-one thousand, two hundred forty-three".
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