1360404354743 has 8 divisors (see below), whose sum is σ = 1636576667520. Its totient is φ = 1104689250360.

The previous prime is 1360404354649. The next prime is 1360404354761. The reversal of 1360404354743 is 3474534040631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1360404354743 - 2⁸ = 1360404354487 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1360404354694 and 1360404354703.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1360404054743) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5114301953 + ... + 5114302218.

It is an arithmetic number, because the mean of its divisors is an integer number (204572083440).

Almost surely, 2^{1360404354743} is an apocalyptic number.

1360404354743 is a deficient number, since it is larger than the sum of its proper divisors (276172312777).

1360404354743 is a wasteful number, since it uses less digits than its factorization.

1360404354743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10228604197.

The product of its (nonzero) digits is 1451520, while the sum is 44.

The spelling of 1360404354743 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred fifty-four thousand, seven hundred forty-three".