1360405206563 has 16 divisors (see below), whose sum is σ = 1506987363840. Its totient is φ = 1220198289696.

The previous prime is 1360405206521. The next prime is 1360405206607. The reversal of 1360405206563 is 3656025040631.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1360405206563 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1360405206563.

It is not an unprimeable number, because it can be changed into a prime (1360405206163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7924145 + ... + 8094002.

It is an arithmetic number, because the mean of its divisors is an integer number (94186710240).

Almost surely, 2^{1360405206563} is an apocalyptic number.

1360405206563 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1360405206563 is a deficient number, since it is larger than the sum of its proper divisors (146582157277).

1360405206563 is a wasteful number, since it uses less digits than its factorization.

1360405206563 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16018346.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 1360405206563 in words is "one trillion, three hundred sixty billion, four hundred five million, two hundred six thousand, five hundred sixty-three".