136041042668051 has 4 divisors (see below), whose sum is σ = 138935532937632. Its totient is φ = 133146552398472.

The previous prime is 136041042668021. The next prime is 136041042668077. The reversal of 136041042668051 is 150866240140631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136041042668051 - 2³⁰ = 136039968926227 is a prime.

It is a super-2 number, since 2×136041042668051² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (47), and also a Moran number because the ratio is a prime number: 2894490269533 = 136041042668051 / (1 + 3 + 6 + 0 + 4 + 1 + 0 + 4 + 2 + 6 + 6 + 8 + 0 + 5 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136041042667987 and 136041042668005.

It is not an unprimeable number, because it can be changed into a prime (136041042668021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1447245134720 + ... + 1447245134813.

It is an arithmetic number, because the mean of its divisors is an integer number (34733883234408).

Almost surely, 2^{136041042668051} is an apocalyptic number.

136041042668051 is a deficient number, since it is larger than the sum of its proper divisors (2894490269581).

136041042668051 is an equidigital number, since it uses as much as digits as its factorization.

136041042668051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2894490269580.

The product of its (nonzero) digits is 829440, while the sum is 47.

The spelling of 136041042668051 in words is "one hundred thirty-six trillion, forty-one billion, forty-two million, six hundred sixty-eight thousand, fifty-one".