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1360534454053 = 3307411410479
BaseRepresentation
bin10011110011000110001…
…011000011111100100101
311211001202222121100002221
4103303012023003330211
5134242333310012203
62521004303032341
7200203212022225
oct23630613037445
94731688540087
101360534454053
11484aaa259515
1219b82029b6b1
139b3b44b0b18
1449bc9002085
15255cd549abd
hex13cc62c3f25

1360534454053 has 4 divisors (see below), whose sum is σ = 1360945867840. Its totient is φ = 1360123040268.

The previous prime is 1360534454033. The next prime is 1360534454087. The reversal of 1360534454053 is 3504544350631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1360534454053 - 217 = 1360534322981 is a prime.

It is a super-3 number, since 3×13605344540533 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1360534454033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205701933 + ... + 205708546.

It is an arithmetic number, because the mean of its divisors is an integer number (340236466960).

Almost surely, 21360534454053 is an apocalyptic number.

It is an amenable number.

1360534454053 is a deficient number, since it is larger than the sum of its proper divisors (411413787).

1360534454053 is an equidigital number, since it uses as much as digits as its factorization.

1360534454053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 411413786.

The product of its (nonzero) digits is 1296000, while the sum is 43.

The spelling of 1360534454053 in words is "one trillion, three hundred sixty billion, five hundred thirty-four million, four hundred fifty-four thousand, fifty-three".

Divisors: 1 3307 411410479 1360534454053