Base | Representation |
---|---|
bin | 10011110011000110100… |
… | …000101110101111001001 |
3 | 11211001210101021221000010 |
4 | 103303012200232233021 |
5 | 134242341233244340 |
6 | 2521005024502133 |
7 | 200203311220650 |
oct | 23630640565711 |
9 | 4731711257003 |
10 | 1360540134345 |
11 | 485002489177 |
12 | 19b82217a949 |
13 | 9b3b571c442 |
14 | 49bc9a80197 |
15 | 255cdcbcb80 |
hex | 13cc682ebc9 |
1360540134345 has 32 divisors (see below), whose sum is σ = 2487892119552. Its totient is φ = 621949378752.
The previous prime is 1360540134337. The next prime is 1360540134377. The reversal of 1360540134345 is 5434310450631.
It is not a de Polignac number, because 1360540134345 - 23 = 1360540134337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7905684 + ... + 8075946.
It is an arithmetic number, because the mean of its divisors is an integer number (77746628736).
Almost surely, 21360540134345 is an apocalyptic number.
1360540134345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1360540134345 is a deficient number, since it is larger than the sum of its proper divisors (1127351985207).
1360540134345 is a wasteful number, since it uses less digits than its factorization.
1360540134345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246381.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 1360540134345 its reverse (5434310450631), we get a palindrome (6794850584976).
The spelling of 1360540134345 in words is "one trillion, three hundred sixty billion, five hundred forty million, one hundred thirty-four thousand, three hundred forty-five".
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