Base | Representation |
---|---|
bin | 11110111100100011010101… |
… | …011111010000011010011111 |
3 | 122211220021100121120112000221 |
4 | 132330203111133100122133 |
5 | 120314400412341310401 |
6 | 1201244343335502211 |
7 | 40445036650656205 |
oct | 3674432537203237 |
9 | 584807317515027 |
10 | 136102505416351 |
11 | 3a403826139101 |
12 | 133216b1827967 |
13 | 5ac35464cc2a6 |
14 | 2587579a6d075 |
15 | 10b05126b67a1 |
hex | 7bc8d57d069f |
136102505416351 has 4 divisors (see below), whose sum is σ = 136130901520752. Its totient is φ = 136074109311952.
The previous prime is 136102505416343. The next prime is 136102505416357. The reversal of 136102505416351 is 153614505201631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136102505416351 - 23 = 136102505416343 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 136102505416298 and 136102505416307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136102505416357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14198045011 + ... + 14198054596.
It is an arithmetic number, because the mean of its divisors is an integer number (34032725380188).
Almost surely, 2136102505416351 is an apocalyptic number.
136102505416351 is a deficient number, since it is larger than the sum of its proper divisors (28396104401).
136102505416351 is an equidigital number, since it uses as much as digits as its factorization.
136102505416351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28396104400.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 136102505416351 in words is "one hundred thirty-six trillion, one hundred two billion, five hundred five million, four hundred sixteen thousand, three hundred fifty-one".
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