1361130433643 has 8 divisors (see below), whose sum is σ = 1366819331856. Its totient is φ = 1355441875200.

The previous prime is 1361130433631. The next prime is 1361130433673. The reversal of 1361130433643 is 3463340311631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1361130433643 - 2⁴ = 1361130433627 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1361130433597 and 1361130433606.

It is not an unprimeable number, because it can be changed into a prime (1361130433673) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10901255 + ... + 11025407.

It is an arithmetic number, because the mean of its divisors is an integer number (170852416482).

Almost surely, 2^{1361130433643} is an apocalyptic number.

1361130433643 is a deficient number, since it is larger than the sum of its proper divisors (5688898213).

1361130433643 is a wasteful number, since it uses less digits than its factorization.

1361130433643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169885.

The product of its (nonzero) digits is 139968, while the sum is 38.

The spelling of 1361130433643 in words is "one trillion, three hundred sixty-one billion, one hundred thirty million, four hundred thirty-three thousand, six hundred forty-three".