1361130565117 has 4 divisors (see below), whose sum is σ = 1361143181916. Its totient is φ = 1361117948320.

The previous prime is 1361130565057. The next prime is 1361130565139. The reversal of 1361130565117 is 7115650311631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1130126329476 + 231004235641 = 1063074^2 + 480629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1361130565117 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1361130565117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1361130565517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6145168 + ... + 6362809.

It is an arithmetic number, because the mean of its divisors is an integer number (340285795479).

Almost surely, 2^{1361130565117} is an apocalyptic number.

It is an amenable number.

1361130565117 is a deficient number, since it is larger than the sum of its proper divisors (12616799).

1361130565117 is a wasteful number, since it uses less digits than its factorization.

1361130565117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12616798.

The product of its (nonzero) digits is 56700, while the sum is 40.

Adding to 1361130565117 its reverse (7115650311631), we get a palindrome (8476780876748).

The spelling of 1361130565117 in words is "one trillion, three hundred sixty-one billion, one hundred thirty million, five hundred sixty-five thousand, one hundred seventeen".