Base | Representation |
---|---|
bin | 11110111100101110000110… |
… | …100111101001100100010001 |
3 | 122211221101012100221211120012 |
4 | 132330232012213221210101 |
5 | 120320043102140241403 |
6 | 1201253534511124305 |
7 | 40445626320552212 |
oct | 3674560647514421 |
9 | 584841170854505 |
10 | 136114067118353 |
11 | 3a408719446a25 |
12 | 13323999813695 |
13 | 5ac466990358c |
14 | 2587d55397409 |
15 | 10b098c70aed8 |
hex | 7bcb869e9911 |
136114067118353 has 4 divisors (see below), whose sum is σ = 143277965387760. Its totient is φ = 128950168848948.
The previous prime is 136114067118349. The next prime is 136114067118371. The reversal of 136114067118353 is 353811760411631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 136114067118353 - 22 = 136114067118349 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136114067118343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3581949134675 + ... + 3581949134712.
It is an arithmetic number, because the mean of its divisors is an integer number (35819491346940).
Almost surely, 2136114067118353 is an apocalyptic number.
It is an amenable number.
136114067118353 is a deficient number, since it is larger than the sum of its proper divisors (7163898269407).
136114067118353 is an equidigital number, since it uses as much as digits as its factorization.
136114067118353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7163898269406.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 136114067118353 in words is "one hundred thirty-six trillion, one hundred fourteen billion, sixty-seven million, one hundred eighteen thousand, three hundred fifty-three".
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