Base | Representation |
---|---|
bin | 11110111100101110000110… |
… | …100111101001100100100011 |
3 | 122211221101012100221211120212 |
4 | 132330232012213221210203 |
5 | 120320043102140241441 |
6 | 1201253534511124335 |
7 | 40445626320552236 |
oct | 3674560647514443 |
9 | 584841170854525 |
10 | 136114067118371 |
11 | 3a408719446a41 |
12 | 133239998136ab |
13 | 5ac46699035a4 |
14 | 2587d5539741d |
15 | 10b098c70aeeb |
hex | 7bcb869e9923 |
136114067118371 has 2 divisors, whose sum is σ = 136114067118372. Its totient is φ = 136114067118370.
The previous prime is 136114067118349. The next prime is 136114067118559. The reversal of 136114067118371 is 173811760411631.
It is a weak prime.
It is an emirp because it is prime and its reverse (173811760411631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136114067118371 is a prime.
It is not a weakly prime, because it can be changed into another prime (136114067115371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68057033559185 + 68057033559186.
It is an arithmetic number, because the mean of its divisors is an integer number (68057033559186).
Almost surely, 2136114067118371 is an apocalyptic number.
136114067118371 is a deficient number, since it is larger than the sum of its proper divisors (1).
136114067118371 is an equidigital number, since it uses as much as digits as its factorization.
136114067118371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 508032, while the sum is 50.
The spelling of 136114067118371 in words is "one hundred thirty-six trillion, one hundred fourteen billion, sixty-seven million, one hundred eighteen thousand, three hundred seventy-one".
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