Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …101001100110001100111 |
3 | 11211010111210102122110011 |
4 | 103303232031030301213 |
5 | 134300222230300033 |
6 | 2521155054511051 |
7 | 200225645653645 |
oct | 23635615146147 |
9 | 4733453378404 |
10 | 1361206103143 |
11 | 4853143a4407 |
12 | 19b989205487 |
13 | 9b4906a4a13 |
14 | 49c502ba195 |
15 | 2561c4bbccd |
hex | 13cee34cc67 |
1361206103143 has 8 divisors (see below), whose sum is σ = 1398016584560. Its totient is φ = 1324396733760.
The previous prime is 1361206103087. The next prime is 1361206103161. The reversal of 1361206103143 is 3413016021631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1361206103143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361206113143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2600923 + ... + 3080131.
It is an arithmetic number, because the mean of its divisors is an integer number (174752073070).
Almost surely, 21361206103143 is an apocalyptic number.
1361206103143 is a deficient number, since it is larger than the sum of its proper divisors (36810481417).
1361206103143 is an equidigital number, since it uses as much as digits as its factorization.
1361206103143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 556017.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 1361206103143 in words is "one trillion, three hundred sixty-one billion, two hundred six million, one hundred three thousand, one hundred forty-three".
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