Search a number
-
+
13613011161 = 34537670387
BaseRepresentation
bin11001010110110011…
…00001000011011001
31022010201021121200120
430223121201003121
5210334412324121
610130450023453
7661225454121
oct145331410331
938121247616
1013613011161
11585620a852
12277ab77b89
13138c3a48b9
14931d3bc81
1554a18ebc6
hex32b6610d9

13613011161 has 4 divisors (see below), whose sum is σ = 18150681552. Its totient is φ = 9075340772.

The previous prime is 13613011129. The next prime is 13613011169. The reversal of 13613011161 is 16111031631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13613011161 - 25 = 13613011129 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13613011169) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2268835191 + ... + 2268835196.

It is an arithmetic number, because the mean of its divisors is an integer number (4537670388).

Almost surely, 213613011161 is an apocalyptic number.

It is an amenable number.

13613011161 is a deficient number, since it is larger than the sum of its proper divisors (4537670391).

13613011161 is an equidigital number, since it uses as much as digits as its factorization.

13613011161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4537670390.

The product of its (nonzero) digits is 324, while the sum is 24.

Adding to 13613011161 its reverse (16111031631), we get a palindrome (29724042792).

The spelling of 13613011161 in words is "thirteen billion, six hundred thirteen million, eleven thousand, one hundred sixty-one".

Divisors: 1 3 4537670387 13613011161