Base | Representation |
---|---|
bin | 10011110100000001101… |
… | …001010011001000110101 |
3 | 11211011100112002221002111 |
4 | 103310001221103020311 |
5 | 134301404223030331 |
6 | 2521251305011021 |
7 | 200240016025414 |
oct | 23640151231065 |
9 | 4734315087074 |
10 | 1361532236341 |
11 | 4854714a8082 |
12 | 19ba5a483a71 |
13 | 9b513122744 |
14 | 49c8173347b |
15 | 2563ae3ddb1 |
hex | 13d01a53235 |
1361532236341 has 8 divisors (see below), whose sum is σ = 1382354467200. Its totient is φ = 1340755720080.
The previous prime is 1361532236261. The next prime is 1361532236423. The reversal of 1361532236341 is 1436322351631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1361532236341 - 233 = 1352942301749 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1361532236294 and 1361532236303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361532236941) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11368626 + ... + 11487763.
It is an arithmetic number, because the mean of its divisors is an integer number (172794308400).
Almost surely, 21361532236341 is an apocalyptic number.
It is an amenable number.
1361532236341 is a deficient number, since it is larger than the sum of its proper divisors (20822230859).
1361532236341 is an equidigital number, since it uses as much as digits as its factorization.
1361532236341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22857299.
The product of its digits is 233280, while the sum is 40.
Adding to 1361532236341 its reverse (1436322351631), we get a palindrome (2797854587972).
The spelling of 1361532236341 in words is "one trillion, three hundred sixty-one billion, five hundred thirty-two million, two hundred thirty-six thousand, three hundred forty-one".
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