Base | Representation |
---|---|
bin | 10011110100001011110… |
… | …101000110111011001111 |
3 | 11211011210102121220201222 |
4 | 103310023311012323033 |
5 | 134302231443313312 |
6 | 2521320251153555 |
7 | 200244162260435 |
oct | 23641365067317 |
9 | 4734712556658 |
10 | 1361703104207 |
11 | 4855499a2696 |
12 | 19baa77458bb |
13 | 9b53c649aa4 |
14 | 49c9a2d0d55 |
15 | 2564ae41672 |
hex | 13d0bd46ecf |
1361703104207 has 4 divisors (see below), whose sum is σ = 1361828513640. Its totient is φ = 1361577694776.
The previous prime is 1361703104141. The next prime is 1361703104221. The reversal of 1361703104207 is 7024013071631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1361703104207 - 212 = 1361703100111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361703104257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62688428 + ... + 62710145.
It is an arithmetic number, because the mean of its divisors is an integer number (340457128410).
Almost surely, 21361703104207 is an apocalyptic number.
1361703104207 is a deficient number, since it is larger than the sum of its proper divisors (125409433).
1361703104207 is a wasteful number, since it uses less digits than its factorization.
1361703104207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125409432.
The product of its (nonzero) digits is 21168, while the sum is 35.
Adding to 1361703104207 its reverse (7024013071631), we get a palindrome (8385716175838).
The spelling of 1361703104207 in words is "one trillion, three hundred sixty-one billion, seven hundred three million, one hundred four thousand, two hundred seven".
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