Base | Representation |
---|---|
bin | 111111011010001110… |
… | …1100101111111111111 |
3 | 111000111000222012001201 |
4 | 1332310131211333333 |
5 | 4212334420033004 |
6 | 142320102520331 |
7 | 12560313603166 |
oct | 1766435457777 |
9 | 430430865051 |
10 | 136171642879 |
11 | 52828384838 |
12 | 224837360a7 |
13 | cac16a961c |
14 | 683add83dd |
15 | 381eaa36a4 |
hex | 1fb4765fff |
136171642879 has 4 divisors (see below), whose sum is σ = 136958762376. Its totient is φ = 135384523384.
The previous prime is 136171642861. The next prime is 136171642921. The reversal of 136171642879 is 978246171631.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 978246171631 = 691 ⋅1415696341.
It is a cyclic number.
It is not a de Polignac number, because 136171642879 - 25 = 136171642847 is a prime.
It is a super-2 number, since 2×1361716428792 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136171642979) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393559489 + ... + 393559834.
It is an arithmetic number, because the mean of its divisors is an integer number (34239690594).
Almost surely, 2136171642879 is an apocalyptic number.
136171642879 is a deficient number, since it is larger than the sum of its proper divisors (787119497).
136171642879 is an equidigital number, since it uses as much as digits as its factorization.
136171642879 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 787119496.
The product of its digits is 3048192, while the sum is 55.
The spelling of 136171642879 in words is "one hundred thirty-six billion, one hundred seventy-one million, six hundred forty-two thousand, eight hundred seventy-nine".
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