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136225120516643 = 211645616684913
BaseRepresentation
bin11110111110010101100001…
…111010101111101000100011
3122212022222211212111222201202
4132332111201322233220203
5120323403021323013033
61201420542330551415
740456640323063544
oct3676254172575043
9585288755458652
10136225120516643
113a450827171834
121334141129856b
135b01c87415782
14258d48c4284cb
1510b37dc0318e8
hex7be561eafa23

136225120516643 has 4 divisors (see below), whose sum is σ = 136870737201768. Its totient is φ = 135579503831520.

The previous prime is 136225120516609. The next prime is 136225120516669. The reversal of 136225120516643 is 346615021522631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136225120516643 - 210 = 136225120515619 is a prime.

It is a super-2 number, since 2×1362251205166432 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136225120516543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322808342246 + ... + 322808342667.

It is an arithmetic number, because the mean of its divisors is an integer number (34217684300442).

Almost surely, 2136225120516643 is an apocalyptic number.

136225120516643 is a deficient number, since it is larger than the sum of its proper divisors (645616685125).

136225120516643 is an equidigital number, since it uses as much as digits as its factorization.

136225120516643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 645616685124.

The product of its (nonzero) digits is 1555200, while the sum is 47.

The spelling of 136225120516643 in words is "one hundred thirty-six trillion, two hundred twenty-five billion, one hundred twenty million, five hundred sixteen thousand, six hundred forty-three".

Divisors: 1 211 645616684913 136225120516643