Base | Representation |
---|---|
bin | 11001011000001010… |
… | …10111000001111011 |
3 | 1022011111220112111200 |
4 | 30230011113001323 |
5 | 210400333120233 |
6 | 10131540225243 |
7 | 661425243204 |
oct | 145405270173 |
9 | 38144815450 |
10 | 13624504443 |
11 | 586174a930 |
12 | 278299b223 |
13 | 139189a064 |
14 | 9336905ab |
15 | 54b1b0313 |
hex | 32c15707b |
13624504443 has 24 divisors (see below), whose sum is σ = 21484373040. Its totient is φ = 8251330560.
The previous prime is 13624504441. The next prime is 13624504469. The reversal of 13624504443 is 34440542631.
13624504443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13624504443 - 21 = 13624504441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13624504398 and 13624504407.
It is not an unprimeable number, because it can be changed into a prime (13624504441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 90655 + ... + 188327.
It is an arithmetic number, because the mean of its divisors is an integer number (895182210).
Almost surely, 213624504443 is an apocalyptic number.
13624504443 is a deficient number, since it is larger than the sum of its proper divisors (7859868597).
13624504443 is a wasteful number, since it uses less digits than its factorization.
13624504443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99099 (or 99096 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 36.
The spelling of 13624504443 in words is "thirteen billion, six hundred twenty-four million, five hundred four thousand, four hundred forty-three".
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