Base | Representation |
---|---|
bin | 11001011000001101… |
… | …00100000110100111 |
3 | 1022011112111120112222 |
4 | 30230012210012213 |
5 | 210400423221020 |
6 | 10131551102555 |
7 | 661431026453 |
oct | 145406440647 |
9 | 38145446488 |
10 | 13624820135 |
11 | 5861946033 |
12 | 2782b11a5b |
13 | 139197a964 |
14 | 933733663 |
15 | 54b223b25 |
hex | 32c1a41a7 |
13624820135 has 8 divisors (see below), whose sum is σ = 16350436320. Its totient is φ = 10899421344.
The previous prime is 13624820113. The next prime is 13624820149. The reversal of 13624820135 is 53102842631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13624820135 - 26 = 13624820071 is a prime.
It is a super-2 number, since 2×136248201352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13624820095 and 13624820104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161414 + ... + 230876.
It is an arithmetic number, because the mean of its divisors is an integer number (2043804540).
Almost surely, 213624820135 is an apocalyptic number.
13624820135 is a deficient number, since it is larger than the sum of its proper divisors (2725616185).
13624820135 is an equidigital number, since it uses as much as digits as its factorization.
13624820135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 108697.
The product of its (nonzero) digits is 34560, while the sum is 35.
The spelling of 13624820135 in words is "thirteen billion, six hundred twenty-four million, eight hundred twenty thousand, one hundred thirty-five".
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