Base | Representation |
---|---|
bin | 1100011001000101101010… |
… | …0101011000100000010011 |
3 | 1210020112220112211101212202 |
4 | 3012101122211120200103 |
5 | 3241213304414341201 |
6 | 44551151003313415 |
7 | 2604246032130413 |
oct | 306213245304023 |
9 | 53215815741782 |
10 | 13625156012051 |
11 | 438343a3a84a1 |
12 | 164079121b86b |
13 | 77ab0127464c |
14 | 351665264643 |
15 | 18964cc42c6b |
hex | c645a958813 |
13625156012051 has 4 divisors (see below), whose sum is σ = 13625239840272. Its totient is φ = 13625072183832.
The previous prime is 13625156012033. The next prime is 13625156012077. The reversal of 13625156012051 is 15021065152631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13625156012051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13625156011996 and 13625156012014.
It is not an unprimeable number, because it can be changed into a prime (13625156018051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41669831 + ... + 41995536.
It is an arithmetic number, because the mean of its divisors is an integer number (3406309960068).
Almost surely, 213625156012051 is an apocalyptic number.
13625156012051 is a deficient number, since it is larger than the sum of its proper divisors (83828221).
13625156012051 is an equidigital number, since it uses as much as digits as its factorization.
13625156012051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83828220.
The product of its (nonzero) digits is 54000, while the sum is 38.
The spelling of 13625156012051 in words is "thirteen trillion, six hundred twenty-five billion, one hundred fifty-six million, twelve thousand, fifty-one".
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