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136254041245 = 573892972607
BaseRepresentation
bin111111011100101011…
…1111010110010011101
3111000200210000110101001
41332321113322302131
54213022013304440
6142332204550301
712562334145520
oct1767127726235
9430623013331
10136254041245
115286a943963
12224a7252391
13cb0579955a
146847d26bb7
153826e2cb9a
hex1fb95fac9d

136254041245 has 8 divisors (see below), whose sum is σ = 186862685184. Its totient is φ = 93431342544.

The previous prime is 136254041179. The next prime is 136254041257. The reversal of 136254041245 is 542140452631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 136254041245 - 219 = 136253516957 is a prime.

It is a super-2 number, since 2×1362540412452 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1946486269 + ... + 1946486338.

It is an arithmetic number, because the mean of its divisors is an integer number (23357835648).

Almost surely, 2136254041245 is an apocalyptic number.

It is an amenable number.

136254041245 is a deficient number, since it is larger than the sum of its proper divisors (50608643939).

136254041245 is an equidigital number, since it uses as much as digits as its factorization.

136254041245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3892972619.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 136254041245 its reverse (542140452631), we get a palindrome (678394493876).

The spelling of 136254041245 in words is "one hundred thirty-six billion, two hundred fifty-four million, forty-one thousand, two hundred forty-five".

Divisors: 1 5 7 35 3892972607 19464863035 27250808249 136254041245