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13626811382181 = 34542270460727
BaseRepresentation
bin1100011001001011110101…
…0000000111100110100101
31210020201011220200220210120
43012102331100013212211
53241230202203212211
644552023135512153
72604335042422404
oct306227520074645
953221156626716
1013626811382181
114384109858588
121640b73688659
1377b0061c5bba
1435178104d63b
151896e822cd06
hexc64bd4079a5

13626811382181 has 4 divisors (see below), whose sum is σ = 18169081842912. Its totient is φ = 9084540921452.

The previous prime is 13626811382167. The next prime is 13626811382207. The reversal of 13626811382181 is 18128311862631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13626811382181 - 230 = 13625737640357 is a prime.

It is a super-2 number, since 2×136268113821812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13626811382381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2271135230361 + ... + 2271135230366.

It is an arithmetic number, because the mean of its divisors is an integer number (4542270460728).

Almost surely, 213626811382181 is an apocalyptic number.

It is an amenable number.

13626811382181 is a deficient number, since it is larger than the sum of its proper divisors (4542270460731).

13626811382181 is an equidigital number, since it uses as much as digits as its factorization.

13626811382181 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4542270460730.

The product of its digits is 663552, while the sum is 51.

The spelling of 13626811382181 in words is "thirteen trillion, six hundred twenty-six billion, eight hundred eleven million, three hundred eighty-two thousand, one hundred eighty-one".

Divisors: 1 3 4542270460727 13626811382181