Base | Representation |
---|---|
bin | 10011110101011011110… |
… | …010010001001101000001 |
3 | 11211022020220202202210200 |
4 | 103311123302101031001 |
5 | 134313003400142103 |
6 | 2522101330515413 |
7 | 200322341254605 |
oct | 23653362211501 |
9 | 4738226682720 |
10 | 1363044537153 |
11 | 48607811a062 |
12 | 1a0200a35b69 |
13 | 9b6c45308b0 |
14 | 49d86519505 |
15 | 256c8ab80a3 |
hex | 13d5bc91341 |
1363044537153 has 48 divisors (see below), whose sum is σ = 2170296011520. Its totient is φ = 819095277312.
The previous prime is 1363044537121. The next prime is 1363044537187. The reversal of 1363044537153 is 3517354403631.
1363044537153 is a `hidden beast` number, since 1 + 3 + 63 + 0 + 4 + 4 + 537 + 1 + 53 = 666.
It is not a de Polignac number, because 1363044537153 - 25 = 1363044537121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1363044537099 and 1363044537108.
It is not an unprimeable number, because it can be changed into a prime (1363044537653) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2156293 + ... + 2715821.
It is an arithmetic number, because the mean of its divisors is an integer number (45214500240).
Almost surely, 21363044537153 is an apocalyptic number.
1363044537153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1363044537153 is a deficient number, since it is larger than the sum of its proper divisors (807251474367).
1363044537153 is a wasteful number, since it uses less digits than its factorization.
1363044537153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 560038 (or 560035 counting only the distinct ones).
The product of its (nonzero) digits is 1360800, while the sum is 45.
The spelling of 1363044537153 in words is "one trillion, three hundred sixty-three billion, forty-four million, five hundred thirty-seven thousand, one hundred fifty-three".
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