13642305442603 has 4 divisors (see below), whose sum is σ = 14112729768240. Its totient is φ = 13171881116968.

The previous prime is 13642305442547. The next prime is 13642305442639. The reversal of 13642305442603 is 30624450324631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13642305442603 - 2²⁵ = 13642271888171 is a prime.

It is a super-2 number, since 2×13642305442603² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13642305442603.

It is not an unprimeable number, because it can be changed into a prime (13642305542603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235212162775 + ... + 235212162832.

It is an arithmetic number, because the mean of its divisors is an integer number (3528182442060).

Almost surely, 2^{13642305442603} is an apocalyptic number.

13642305442603 is a deficient number, since it is larger than the sum of its proper divisors (470424325637).

13642305442603 is an equidigital number, since it uses as much as digits as its factorization.

13642305442603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470424325636.

The product of its (nonzero) digits is 1244160, while the sum is 43.

The spelling of 13642305442603 in words is "thirteen trillion, six hundred forty-two billion, three hundred five million, four hundred forty-two thousand, six hundred three".