Base | Representation |
---|---|
bin | 1100011010000101100011… |
… | …0001101001100111001011 |
3 | 1210022012011201200211010222 |
4 | 3012201120301221213023 |
5 | 3242003420204330403 |
6 | 45003104425300255 |
7 | 2605424022544643 |
oct | 306413061514713 |
9 | 53265151624128 |
10 | 13642305542603 |
11 | 438a73a908641 |
12 | 1643b7863468b |
13 | 77c60523106a |
14 | 352410b49523 |
15 | 189d03605338 |
hex | c6858c699cb |
13642305542603 has 2 divisors, whose sum is σ = 13642305542604. Its totient is φ = 13642305542602.
The previous prime is 13642305542599. The next prime is 13642305542609. The reversal of 13642305542603 is 30624550324631.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13642305542603 - 22 = 13642305542599 is a prime.
It is a super-2 number, since 2×136423055426032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13642305542609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821152771301 + 6821152771302.
It is an arithmetic number, because the mean of its divisors is an integer number (6821152771302).
Almost surely, 213642305542603 is an apocalyptic number.
13642305542603 is a deficient number, since it is larger than the sum of its proper divisors (1).
13642305542603 is an equidigital number, since it uses as much as digits as its factorization.
13642305542603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1555200, while the sum is 44.
The spelling of 13642305542603 in words is "thirteen trillion, six hundred forty-two billion, three hundred five million, five hundred forty-two thousand, six hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •