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13642320239 = 33141215469
BaseRepresentation
bin11001011010010010…
…10100100101101111
31022012202102200011222
430231021110211233
5210414413221424
610133414133555
7662032544252
oct145511244557
938182380158
1013642320239
115870809129
1227889512bb
131395497252
14935bab099
1554ca2de5e
hex32d25496f

13642320239 has 4 divisors (see below), whose sum is σ = 13683536040. Its totient is φ = 13601104440.

The previous prime is 13642320217. The next prime is 13642320247. The reversal of 13642320239 is 93202324631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13642320239 - 224 = 13625543023 is a prime.

It is a super-4 number, since 4×136423202394 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13642320199 and 13642320208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13642328239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20607404 + ... + 20608065.

It is an arithmetic number, because the mean of its divisors is an integer number (3420884010).

Almost surely, 213642320239 is an apocalyptic number.

13642320239 is a deficient number, since it is larger than the sum of its proper divisors (41215801).

13642320239 is an equidigital number, since it uses as much as digits as its factorization.

13642320239 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41215800.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 13642320239 in words is "thirteen billion, six hundred forty-two million, three hundred twenty thousand, two hundred thirty-nine".

Divisors: 1 331 41215469 13642320239