1364410553351 has 4 divisors (see below), whose sum is σ = 1365020484312. Its totient is φ = 1363800622392.

The previous prime is 1364410553327. The next prime is 1364410553371. The reversal of 1364410553351 is 1533550144631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1364410553351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1364410553299 and 1364410553308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1364410553371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304962125 + ... + 304966598.

It is an arithmetic number, because the mean of its divisors is an integer number (341255121078).

Almost surely, 2^{1364410553351} is an apocalyptic number.

1364410553351 is a deficient number, since it is larger than the sum of its proper divisors (609930961).

1364410553351 is an equidigital number, since it uses as much as digits as its factorization.

1364410553351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 609930960.

The product of its (nonzero) digits is 324000, while the sum is 41.

Adding to 1364410553351 its reverse (1533550144631), we get a palindrome (2897960697982).

The spelling of 1364410553351 in words is "one trillion, three hundred sixty-four billion, four hundred ten million, five hundred fifty-three thousand, three hundred fifty-one".