Base | Representation |
---|---|
bin | 1100011010001101110110… |
… | …1100000101010101001011 |
3 | 1210022101221010200000011001 |
4 | 3012203131230011111023 |
5 | 3242023002033444003 |
6 | 45004114004115431 |
7 | 2605533210510310 |
oct | 306433554052513 |
9 | 53271833600131 |
10 | 13644535453003 |
11 | 43906846072a4 |
12 | 164449b395b77 |
13 | 77c89c205980 |
14 | 352582d70d07 |
15 | 189dd427e61d |
hex | c68ddb0554b |
13644535453003 has 16 divisors (see below), whose sum is σ = 17110128643776. Its totient is φ = 10591984391040.
The previous prime is 13644535453001. The next prime is 13644535453049. The reversal of 13644535453003 is 30035453544631.
13644535453003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13644535453003 - 21 = 13644535453001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13644535453001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1414523008 + ... + 1414532653.
It is an arithmetic number, because the mean of its divisors is an integer number (1069383040236).
Almost surely, 213644535453003 is an apocalyptic number.
13644535453003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13644535453003 is a deficient number, since it is larger than the sum of its proper divisors (3465593190773).
13644535453003 is a wasteful number, since it uses less digits than its factorization.
13644535453003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2829055734.
The product of its (nonzero) digits is 3888000, while the sum is 46.
Adding to 13644535453003 its reverse (30035453544631), we get a palindrome (43679988997634).
The spelling of 13644535453003 in words is "thirteen trillion, six hundred forty-four billion, five hundred thirty-five million, four hundred fifty-three thousand, three".
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