Base | Representation |
---|---|
bin | 10011110110110000100… |
… | …101101110110000010001 |
3 | 11211102221001222022021122 |
4 | 103312300211232300101 |
5 | 134323412113014211 |
6 | 2522454433532025 |
7 | 200402525542253 |
oct | 23666045566021 |
9 | 4742831868248 |
10 | 1364467313681 |
11 | 48673825512a |
12 | 1a0539414015 |
13 | 9b8902254b4 |
14 | 4a07d479cd3 |
15 | 2575d95b6db |
hex | 13db096ec11 |
1364467313681 has 4 divisors (see below), whose sum is σ = 1364659418112. Its totient is φ = 1364275209252.
The previous prime is 1364467313597. The next prime is 1364467313687. The reversal of 1364467313681 is 1863137644631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1364467313681 is a prime.
It is a super-2 number, since 2×13644673136812 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1364467313687) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96041561 + ... + 96055766.
It is an arithmetic number, because the mean of its divisors is an integer number (341164854528).
Almost surely, 21364467313681 is an apocalyptic number.
It is an amenable number.
1364467313681 is a deficient number, since it is larger than the sum of its proper divisors (192104431).
1364467313681 is an equidigital number, since it uses as much as digits as its factorization.
1364467313681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192104430.
The product of its digits is 5225472, while the sum is 53.
The spelling of 1364467313681 in words is "one trillion, three hundred sixty-four billion, four hundred sixty-seven million, three hundred thirteen thousand, six hundred eighty-one".
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