1365004065631 has 4 divisors (see below), whose sum is σ = 1365008020632. Its totient is φ = 1365000110632.

The previous prime is 1365004065613. The next prime is 1365004065653. The reversal of 1365004065631 is 1365604005631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1365004065631 - 2⁵ = 1365004065599 is a prime.

It is a super-2 number, since 2×1365004065631² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1365004065031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1404445 + ... + 2168518.

It is an arithmetic number, because the mean of its divisors is an integer number (341252005158).

Almost surely, 2^{1365004065631} is an apocalyptic number.

1365004065631 is a deficient number, since it is larger than the sum of its proper divisors (3955001).

1365004065631 is an equidigital number, since it uses as much as digits as its factorization.

1365004065631 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3955000.

The product of its (nonzero) digits is 194400, while the sum is 40.

The spelling of 1365004065631 in words is "one trillion, three hundred sixty-five billion, four million, sixty-five thousand, six hundred thirty-one".