Search a number
-
+
13654001113 = 25753128409
BaseRepresentation
bin11001011011101011…
…11000010111011001
31022020120102010022221
430231311320113121
5210430411013423
610134512344041
7662234044264
oct145565702731
938216363287
1013654001113
115877367145
122790845021
131397a26bcc
1493756bcdb
1554da89e5d
hex32dd785d9

13654001113 has 4 divisors (see below), whose sum is σ = 13707129780. Its totient is φ = 13600872448.

The previous prime is 13654001099. The next prime is 13654001131. The reversal of 13654001113 is 31110045631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12407063769 + 1246937344 = 111387^2 + 35312^2 .

It is a cyclic number.

It is not a de Polignac number, because 13654001113 - 233 = 5064066521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13654001213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26563948 + ... + 26564461.

It is an arithmetic number, because the mean of its divisors is an integer number (3426782445).

Almost surely, 213654001113 is an apocalyptic number.

It is an amenable number.

13654001113 is a deficient number, since it is larger than the sum of its proper divisors (53128667).

13654001113 is an equidigital number, since it uses as much as digits as its factorization.

13654001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53128666.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 13654001113 its reverse (31110045631), we get a palindrome (44764046744).

The spelling of 13654001113 in words is "thirteen billion, six hundred fifty-four million, one thousand, one hundred thirteen".

Divisors: 1 257 53128409 13654001113