1365421234031 has 4 divisors (see below), whose sum is σ = 1382705047200. Its totient is φ = 1348137420864.

The previous prime is 1365421234027. The next prime is 1365421234049. The reversal of 1365421234031 is 1304321245631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1365421234031 - 2² = 1365421234027 is a prime.

It is a super-3 number, since 3×1365421234031³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1365421233982 and 1365421234000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1365421239031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8641906466 + ... + 8641906623.

It is an arithmetic number, because the mean of its divisors is an integer number (345676261800).

Almost surely, 2^{1365421234031} is an apocalyptic number.

1365421234031 is a deficient number, since it is larger than the sum of its proper divisors (17283813169).

1365421234031 is an equidigital number, since it uses as much as digits as its factorization.

1365421234031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17283813168.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 1365421234031 its reverse (1304321245631), we get a palindrome (2669742479662).

The spelling of 1365421234031 in words is "one trillion, three hundred sixty-five billion, four hundred twenty-one million, two hundred thirty-four thousand, thirty-one".