Base | Representation |
---|---|
bin | 11001011011110001… |
… | …01111101110000101 |
3 | 1022020121211021112111 |
4 | 30231320233232011 |
5 | 210431104032013 |
6 | 10134540421021 |
7 | 662243322661 |
oct | 145570575605 |
9 | 38217737474 |
10 | 13654752133 |
11 | 587782a420 |
12 | 2790b47771 |
13 | 1397c2a9b9 |
14 | 9376c58a1 |
15 | 54db8773d |
hex | 32de2fb85 |
13654752133 has 4 divisors (see below), whose sum is σ = 14896093248. Its totient is φ = 12413411020.
The previous prime is 13654752131. The next prime is 13654752169. The reversal of 13654752133 is 33125745631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13654752133 - 21 = 13654752131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13654752131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620670541 + ... + 620670562.
It is an arithmetic number, because the mean of its divisors is an integer number (3724023312).
Almost surely, 213654752133 is an apocalyptic number.
It is an amenable number.
13654752133 is a deficient number, since it is larger than the sum of its proper divisors (1241341115).
13654752133 is a wasteful number, since it uses less digits than its factorization.
13654752133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1241341114.
The product of its digits is 226800, while the sum is 40.
The spelling of 13654752133 in words is "thirteen billion, six hundred fifty-four million, seven hundred fifty-two thousand, one hundred thirty-three".
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