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136554365113 = 1531233338231
BaseRepresentation
bin111111100101101000…
…1100100000010111001
3111001110201010111021021
41333023101210002321
54214130404140423
6142422053542441
712602641644355
oct1771321440271
9431421114237
10136554365113
1152a04419701
122256b944a21
13cb52a7b89a
146875b82465
1538434a295d
hex1fcb4640b9

136554365113 has 8 divisors (see below), whose sum is σ = 136705703616. Its totient is φ = 136403110800.

The previous prime is 136554365069. The next prime is 136554365161. The reversal of 136554365113 is 311563455631.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136554365113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 136554365113.

It is not an unprimeable number, because it can be changed into a prime (136554365413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3552708 + ... + 3590938.

It is an arithmetic number, because the mean of its divisors is an integer number (17088212952).

Almost surely, 2136554365113 is an apocalyptic number.

It is an amenable number.

136554365113 is a deficient number, since it is larger than the sum of its proper divisors (151338503).

136554365113 is a wasteful number, since it uses less digits than its factorization.

136554365113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42095.

The product of its digits is 486000, while the sum is 43.

The spelling of 136554365113 in words is "one hundred thirty-six billion, five hundred fifty-four million, three hundred sixty-five thousand, one hundred thirteen".

Divisors: 1 1531 2333 38231 3571823 58531661 89192923 136554365113