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136563121346 = 268281560673
BaseRepresentation
bin111111100101111001…
…0111101110011000010
3111001111022121100120012
41333023302331303002
54214140124340341
6142423005344522
712603106243631
oct1771362756302
9431438540505
10136563121346
1152a0935a363
1222572868142
13cb548262a2
146876dc1518
1538441320eb
hex1fcbcbdcc2

136563121346 has 4 divisors (see below), whose sum is σ = 204844682022. Its totient is φ = 68281560672.

The previous prime is 136563121339. The next prime is 136563121397. The reversal of 136563121346 is 643121365631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131272159225 + 5290962121 = 362315^2 + 72739^2 .

It is a super-2 number, since 2×1365631213462 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34140780335 + ... + 34140780338.

Almost surely, 2136563121346 is an apocalyptic number.

136563121346 is a deficient number, since it is larger than the sum of its proper divisors (68281560676).

136563121346 is an equidigital number, since it uses as much as digits as its factorization.

136563121346 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68281560675.

The product of its digits is 233280, while the sum is 41.

Adding to 136563121346 its reverse (643121365631), we get a palindrome (779684486977).

The spelling of 136563121346 in words is "one hundred thirty-six billion, five hundred sixty-three million, one hundred twenty-one thousand, three hundred forty-six".

Divisors: 1 2 68281560673 136563121346